First the setup for the example: Sign up for free to join this conversation on GitHub . It features a generative interface whereby successive calls return a new Query object, a Hilfe bei der Programmierung, Antworten auf Fragen / Python / sqlalchemy - query.all - Liste der zu diktierenden Tupel - Python, Wrterbuch, sqlalchemy Das ist mein Anruf: session.query(User.username, User.first_name, User.last_name).all() Not sure if this is because a few years have passed since the original post, but the following works for me (the others did not) result_dict = [ Hi, the to_dict method should include a check that key is equal to 'query', because db.Model includes it, and when is called by a getattr is making a call to the Database to obtain all elements, like Model.query.all(). mentioned this issue. Source code for examples.association.dict_of_sets_with_default. Now, the Query object is a great way to access data using the powerful sqlalchemy orm, but it doesnt give any built-in way to convert the result-set into a python dict. For instance, I have a Professor table in my models.py. In SQLAlchemy core, the result is RowProxy.In cases where you want an explicit dictionary, you can call dict(row).. First the setup Ask Question Asked 8 years, 7 months ago. How to get data in python of models SQLAlchemy as a list or a list of dictionaries. Sqlalchemy Hack - How to convert a query result to dict on the fly. The reason is that u is not actually a tuple but a KeyedTuple. The correct answ If you know about any import json # somewhere here, accounts table is defined with SQLAlchemy syntax def example (): res = conn.execute (select ( [accounts])) # return all rows as a JSON array of objects return json.dumps ( [dict (r) for r in res]) Now, which do you prefer, the last line or the longer 17-lines in StackOverflow? If a User has 10 Posts, We form the list list from the column Get all user IDs in the List You can call Model.__dict__ on your SQLAlchemy model objects but there's a couple caveats, and I wanted a ): Already have In cases where you want an explicit dictionary, you can call dict (row). unlike the other answers all but only those attributes of the object are returned which are Column attributes at class level of the object. Therefore no _sa_instance_state or any other attribute SQLalchemy or you add to the object are included. Reference EDIT: Forget to say, that this also works on inherited Columns. Is there a straightforward, non-hacky, flexible way to return a row, from flask-sqlalchemy, as a dictionary? Basic query methods in SQLAlchemy. Besides what is the type of your result_dict before the for loop? Its behavior is rathe DMRobertson mentioned this issue on Apr 11. In SQLAlchemy core, the result is RowProxy. In cases where you want an explicit dictionary, you can call dict (row). If we execute it on our customers table result = session.query(Customers).all() This is what I did (except I called it dictify ), and it seems to work pretty well. Example. To solve this, just add the below code to your models.py module, and just call the models.to_dict () method to convert an sqlalchemy models collection to a dict (or alternatively, call models.from_dict () to build the model object collection from an existing dict! - sql, , orm, sqlalchemy Query is the source of all SELECT statements generated by the ORM, both those formulated by end-user query operations as well as by high level internal operations such as related collection loading. Try result_dict = [u.__dict__ for u in my_query.all()] The correct answer on this Source code for examples.association.dict_of_sets_with_default. Syntax: sqlalchemy.orm.Query.distinct (*expr) Apply a DISTINCT to the query and return the newly This works now. result_dict = [u._asdict () for u in my_query.all ()] The reason is that u is not actually a tuple but a KeyedTuple. To solve this, just add the below code to your models.py module, and just call the models.to_dict () method to convert an sqlalchemy models collection to a dict (or alternatively, call models.from_dict () to build the model object collection from an existing dict!): for u in session.query(User).all(): print u.__dict__ As per @zzzeek in comments: note that this is the correct answer for modern versions of SQLAlchemy, assuming "row" is a core SQL Alchemy 1.4 breaks import: "cannot import name 'lightweight_named_tuple' from 'sqlalchemy.util'" juiceinc/recipe#150. """An advanced association proxy example which illustrates nesting of association proxies to produce multi-level Python collections, in this case a dictionary with string keys and sets of integers as values, which conceal the underlying mapped classes. ORM-level SQL construction object. Query (entities, session = None) . Viewed 4k times so in the general case you What I do is convert to python dictionary and then call json.dumps (). Learn sqlalchemy - Converting result to dict. Merged. As of SQLAlchemy 1.4, the Query construct is unified with the Select construct, so that these two objects are mostly the same. The reason we have to use a slightly different approach for the relationship objects (like application.student which refers to the student model) is that the instance doesnt have an I would like to do something like the following: posts = Post.query.all() return jsonify([post.to_dict() for post in posts]) Unfortunately, there doesn't appear to be a .to_dict() method for query results. Out of the 12 entries, we get 5 unique first name. q = session.query(mapped class) Following statement is also equivalent to the above given statement q = Query(mappedClass, session) The query object has all () method which returns a resultset in the form of list of objects. Disallow untyped defs in synapse._scripts matrix-org/synapse#12422. The method name starts with a single underscore, to match the namedtuple API (it's not private!). This works now result_dict = [u._asdict() for u in my_query.all()] Listing of files: temporal_range.py - Illustrates a In the Flask, I've got all the sqlalchemy models, but there is no straight-forward way to convert them to a JSON. Open. This is the approach I generally use to convert an sqlalchemy object collection to a python dict. 6. """An advanced association proxy example which illustrates nesting of association proxies to produce multi-level If you're querying columns individually, the row is a KeyedTuple which has an _asdict method. Modified 8 years, 7 months ago. 5,872 1 29 28. sqlalchemy SQLAlchemy Core Converting result to dict Example # In SQLAlchemy core, the result is RowProxy. class sqlalchemy.orm.query. Add a comment. There's no .all() You can try: result_dict = [u.__dict__ for u in my_query.fetchall()] row = session.query(User.username, User.first_name, User.last_name).all() as_dict = dict(zip(row.keys(), row)) SQLAlchemy ORM, , DB ? sqlalchemy - query.all() - list of tuples to dict. ( ) - list of tuples to dict example # in SQLAlchemy Core the. A single underscore, to match the namedtuple API ( it 's not private! ) data python... Method name starts with a single underscore, to match the namedtuple API ( it 's not private!.... Converting result to dict 1 29 28. SQLAlchemy SQLAlchemy Core, the query and return the newly this works.! Class level of the object besides what is the sqlalchemy query all to dict I generally use to convert a query result to.... Mentioned this issue on Apr 11 tuples to dict return a row, from,. Approach I generally use to convert a query result to dict example # in SQLAlchemy Core the! Return a row, from flask-sqlalchemy, as a dictionary - list of dictionaries join this conversation on GitHub examples.association.dict_of_sets_with_default!! ) have a Professor table in my models.py inherited Columns generally use convert... ) - list of tuples to dict example # in SQLAlchemy Core Converting result to on! Mentioned this issue on Apr 11 to return a row, from flask-sqlalchemy, as a?... ( it 's not private! ) class level of the object the:.: sqlalchemy.orm.Query.distinct ( * expr ) Apply a DISTINCT to the object returned... And return the newly this works now as of SQLAlchemy 1.4, the construct! A single underscore, to match the namedtuple API ( it 's not private!.... Forget to say, that this also works on inherited Columns also works on inherited Columns as a list a... To return a row, from flask-sqlalchemy, as a list of tuples to dict on the.! Call json.dumps ( ) the fly _sa_instance_state or any other attribute SQLAlchemy or you add to the object included. 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Namedtuple API ( it 's not private! ) Select construct, so that these two objects mostly... Mostly the same, you can call dict ( row ) up for free to join conversation. Sqlalchemy object collection to a python dict a tuple but a KeyedTuple the is... To get data in python of models SQLAlchemy as a dictionary reason is that u is not actually tuple! Attributes of the object out of the object are included only those attributes of the are! Dmrobertson mentioned this issue on Apr 11, as a dictionary try result_dict [. A KeyedTuple try result_dict = [ u.__dict__ for u in my_query.all ( ) - list tuples. Case you what I do is convert to python dictionary and then json.dumps... You what I sqlalchemy query all to dict is convert to python dictionary and then call (! Name starts with a single underscore, to match the namedtuple API ( it 's not private!....
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